A 51.9 g sample of quartz is put into a calorimeter (see sketch at right) that contains 300.0 g of water. The quartz sample starts off at 97.8 °C and the temperature of the water starts off at 17.0 °C. When the temperature of the water stops changing it's 19.3 °C. The pressure remains constant at 1 atm. insulated container water sample Calculate the specific heat capacity of quartz according to this experiment. Be sure your answer is rounded to 2 significant digits. a calorimeter g °C.

Respuesta :

Answer:

The specific heat capacity of quartz is 0.71 J/g°C.

Explanation:

Heat lost by quartz will be equal to heat gained by the water

[tex]-Q_1=Q_2[/tex]

Mass of quartz= [tex]m_1=51.9 g[/tex]

Specific heat capacity of quartz= [tex]c_1=? [/tex]

Initial temperature of the quartz= [tex]T_1=97.8^oC[/tex]

Final temperature = [tex]T_2=T  = 19.3^oC[/tex]

[tex]Q_1=m_1c_1\times (T-T_1)[/tex]

Mass of water=[tex]m_2=300.0 g[/tex]

Specific heat capacity of water= [tex]c_2=4.18 J/g^oC [/tex]

Initial temperature of the water = [tex]T_3=17.0 ^oC[/tex]

Final temperature of water = [tex]T_2=T

=19.3^oC[/tex]

[tex]Q_2=m_2c_2\times (T-T_3)[/tex]

[tex]-Q_1=Q_2[/tex]

[tex]-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)[/tex]

On substituting all values:

[tex]-(51.9 gc_1\times (19.3^oC-97.8^oC))=300.0 g\times 4.18 J/g^oC\times (19.3^oC-170^oC)[/tex]

we get:

[tex]c_1 =0.7079 J/g^oC\approx 0.71 J/g^oC[/tex]

The specific heat capacity of quartz is 0.71 J/g°C.

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