Answer:
T=1263.16N
Explanation:
A 958-N rocket is coming in for a vertical landing. It starts with a downward speed of 25 m/s and must reduce its speed to 0m/s in 8.0 seconds for the final landing. During this landing maneuver, what must be the thrust due to the rockets engines?
force is that which tends to cane a body state of rest or uniform motion in a straight line
it is also the pull or pus on an object.
the forces involved here to get the thrust on an object, are the weight and the force of gravity
W=mg
958=m*9.81
m=958/9.81
m=97.655kg
T=m(g+a)................................1
to get a
v=u+at
a=dv/dt
a=25/8
a=3.125m/s^2
acceleration is change in velocity per time
juxtaposing into the equation 1
T=97.655(9.81+3.125)
T=1263.16N
