Answer:
x ≥ 661.424°F or x[661.424,∞) and x ≤ - 27°F or x(-∞,-27]
Step-by-step explanation:
The melting point of the substance is - 32.78°C, then the melting point in °F is given by
[tex]C = \frac{5}{9} (F - 32)[/tex]
⇒ [tex]F - 32 = \frac{9}{5}C[/tex]
⇒ [tex]F = 32 + \frac{9}{5} (-32.78)[/tex]
⇒ F = - 27.004°F
Again, the boiling point of the substance is 349.68°C, hence, the boiling point in °F is
[tex]F = 32 + \frac{9}{5} (349.68)[/tex]
⇒ F = 661.424°F
Therefore, the range of temperature in °F for which the substance will not be in liquid state will be x ≥ 661.424°F or x[661.424,∞) and x ≤ - 27.004°F or x(-∞,-27.004], where x is the temperature of the substance in °F. (Answer)
