Answer
given,
mass of block = 0.21 Kg
speed = 1.70 m/s
spring constant = k = 4.50 N/m
using conservation of energy
a) K.E = P.E
[tex]\dfrac{1}{2}mv^2 = \dfrac{1}{2}kx^2[/tex]
[tex]\dfrac{1}{2}\times 0.21 \times 1.7^2 = \dfrac{1}{2}\times 4.5 \times x^2[/tex]
[tex]0.1348= x^2[/tex]
x = 0.367 m
b) if the track is not friction less the maximum compression will be same as the compression in the part a.
