Answer:
The time depends on the distance that they have to travel
[tex]x(t) = \frac{0.3846t^{2} }{2}[/tex]
Explanation:
The only horizontal force exerts over the car and you, it is the force that your friend is applied
Newton's Second Law of Motion defines the relationship between acceleration, force, and mass, thus
[tex]\sum{F} = ma[/tex]
550 = 1430a
a = 0.3846 m/s2
The car and you have a motion under constant acceleration, then theirs position to a time-based is:
[tex]x(t) = x_{0} + v_{0}t +\frac{at^{2} }{2}[/tex]
By the initial conditions
[tex]x(t) = \frac{at^{2} }{2}[/tex]
[tex]x(t) = \frac{0.3846t^{2} }{2}[/tex]
The time depends on the distance that they have to travel
