The distances are:
- E and F: 4 units.
- C and D: 5 units.
- G and H: 3 units.
- A and B: 6 units.
Why?
We can find the distance between each pair of points using the following formula:
[tex]d(P_1,P_2)=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}[/tex]
So, calculating we have:
- E(-2, -1) and F(-2, -5):
[tex]d(E,F)=\sqrt{(-2-(-2))^{2}+(-5-(-1))^{2}}\\\\d(E,F)=\sqrt{0+(-5+1)^{2}}=\sqrt{0+(-4)^{2}}=\sqrt{16}=4units[/tex]
- C(-4, 1) and D(1, 1):
[tex]d(C,D)=\sqrt{(1-(-4))^{2}+(1-(1))^{2}}\\\\d(C,D)=\sqrt{(5)^{2}+0^{2}}=\sqrt{25+0}=\sqrt{25}=5units[/tex]
- G(3, -5) and H(6, -5):
[tex]d(G,H)=\sqrt{(6-(3))^{2}+(-5-(-5))^{2}}\\\\d(G,H)=\sqrt{(3)^{2}+0^{2}}=\sqrt{9+0}=\sqrt{9}=3units[/tex]
- A(5, 4) and B( 5, -2):
[tex]d(A,B)=\sqrt{(5-(5))^{2}+(-2-(4))^{2}}\\\\d(A,B)=\sqrt{0+(-6)^{2}}=\sqrt{0+36}=\sqrt{36}=6units[/tex]
Have a nice day!
Answer:
G(3, -5) and H(6, -5) ------>3 units
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E(-2, -1) and F(-2, -5)------->4 units
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A (5, 4) and B( 5, -2)------->6 units
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C(-4, 1) and D(1, 1)---------->5 units
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Explanation:
