The ages of 3 brothers are represented by consecutive integers. If the oldest brother's age is decreased by twice the younger brother's age, the result is -19. How old is the youngest brother?

Respuesta :

Answer:

The age of youngest brother is 21.

Step-by-step explanation:

Given:

The ages of 3 brothers are represented by consecutive integers.

If the oldest brother's age is decreased by twice the younger brother's age, the result is -19.

Now, to find the age of youngest brother.

Let the age of youngest brother be [tex]a-1.[/tex]

Let the age of middle one be [tex]a[/tex].

And the age of oldest brother age be [tex]a+1.[/tex]

According to question:

[tex](a+1)-2(a-1)=-19[/tex]

⇒ [tex]a+1-2a+2=-19[/tex]

⇒ [tex]-a+3=-19[/tex]

Adding [tex]a[/tex] on both sides we get:

⇒ [tex]2=-19+a[/tex]

Adding 19 on both sides we get:

⇒ [tex]22=a[/tex]

Now, getting the age of youngest brother by putting the value of [tex]a[/tex] :

[tex]a-1[/tex]

⇒ [tex]=22-1=21.[/tex]

Therefore, the age of youngest brother is 21.

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