Answer:
0.001%
Step-by-step explanation:
Given that a recent study conducted by the state government attempts to determine whether the voting public supports a further increase in cigarette taxes to help the public schools
n = 1500
favour x = 622
Sample proportion p = [tex]622/1500 = 0.4147[/tex]
[tex]H_0: p = 0.66\\H_a: p >0.66[/tex]
(right tailed test)
Assume H0 to be true.
Std error = [tex]\sqrt{\frac{0.66*0.34}{1500} } \\=0.01223[/tex]
p difference = -0.2453
Test statistic Z = [tex]\frac{-0.2453}{0.01223} \\=-20.05[/tex]
p value <0.00001
Hence fon ull hypothesis not to be rejected significant level should be greater than 0.00001 or 0.001%