Answer:
875
Step-by-step explanation:
As given, there is a three digit number
So, let assume three digit number be `xyz`.
Now, as given tens digit is 2 greater than the unit digit.
∴ [tex]y= 2+z[/tex]
Next, the hundred digit one greater than the tens digit.
∴[tex]x= 1+y[/tex]
The sum of the tens and the hundreds digits is three times the units digit.
∴[tex]x+y= 3z[/tex]
Now, substituting the value in the equation.
[tex]x+y= 3z[/tex]
⇒ [tex](1+y)+y= 3\times (y-2)[/tex]
solving it to get value of y
⇒ [tex]2y+1= 3y-6[/tex]
⇒[tex]-y= -7[/tex]
∴ [tex]y=7[/tex]
Next, finding value of z
y= [tex]2+z[/tex]
substituting the value of y and subtracting both side by 2
∴ z= [tex]7-2= 5[/tex]
Last, finding the value of x
[tex]x=1+y[/tex]
substituting the value of y
∴ x= 8
xyz= 875
