Answer:
Explanation:
Given
Kinetic energy varies jointly as mass and square of velocity
[tex]K.E.\propto m[/tex]
[tex]K.E.\propto v^2[/tex]
[tex]K.E.=kmv^2[/tex]
for [tex]m=15 gm\ and\ v=3 cm/s[/tex]
[tex]K.E.=27 ergs[/tex]
[tex]27=k(15)(3)^2 -----1[/tex]
for [tex]m=5 gm, v=9 cm/s[/tex]
[tex]K.E.=k(5)(9)^2----2[/tex]
Divide 1 & 2 we get
[tex]\frac{27}{K.E.}=\frac{15\times 3^2}{5\times 9^2}[/tex]
[tex]K.E.=81 ergs[/tex]
