Answer:
The midpoints are ( 5, 6 ).
Step-by-step explanation:
Given that the endpoints are H ( 3, 8) and K (7, 4)-
As we know that-
If a line segment AB is with endpoints ( [tex]x_{1}, y_{1}[/tex]) and ( [tex]x_{2}, y_{2}[/tex] ) then the mid points C are-
C = ( [tex]\frac{x_{1} + x_{2}} {2}[/tex] , [tex]\frac{ y_{1} + y_{2} }{2}[/tex] )
Here,
H ( 3, 8 ) and K ( 7, 4 )
then the midpoints C are-
C = ( [tex]\frac{3 + 7 }{2}[/tex] , [tex]\frac{ 8 + 4 }{2}[/tex]
C= ( 10/2 , 12/2 )
C = ( 5, 6 )
Hence the midpoints are (5, 6).
