Answer:
0.1470
Step-by-step explanation:
Hypothesis : H_0:=0.37 Vs H_1:[tex]\neq[\tex] 0.30
The test statistic under H_o is given by ,
Z=[tex]\frac{p-p_0}{\sqrt{(p_0 q_0)/n}}\rightarrow N(0,1)[/tex]
=[tex]\frac{0.30-0.37}{\sqrt{0.37\times0.63/100}}[/tex]
=[tex]\frac{-0.07}{\sqrt{0.00233}}[/tex]
=-1.45
P value : P value = 2*P ( Z > | Z cal | )
= 2*P ( Z > 1.45 )
= 2*0.07352
= 0.14704
