contestada

Be sure to answer all parts. Use MO diagrams and the bond orders you obtain from them to answer the following questions. (a) Is O2− stable? Yes No (b) Is O2− paramagnetic? Yes No (c) What is the outer (valence) electron configuration of O2−? (σ1s)2(σ*1s)2(σ2s)2(σ*2s)2(σ2p)2(π2p)2(π2p)2(π*2p)2(π*2p)1 (σ2s)2(σ*2s)2(σ2p)2(π2p)2(π2p)2(π*2p)2(π*2p)1 (σ1s)2(σ*1s)2(σ2s)2(π2p)2(π2p)2(π*2p)2(π*2p)1 (σ2s)2(σ*2s)2(σ2p)2(σ2p)2(π2p)2(π*2p)2(π*2p)1

Respuesta :

pstnonsonjoku

Answer:

a) yes b) no c) (σ2s)2(σ*2s)2(σ2p)2(σ2p)2(π2p)2(π*2p)2(π*2p)1

Explanation:

The stability of a molecule depends on the number of bonding and antibonding electrons present. In the O22- ion, there are 10 bonding and 8 antibonding electrons. From the formula bond order= bonding electrons- antibonding electrons/2, we realize that the bond order is 1 meaning that the ion is stable. All the electrons are paired so it isn't paramagnetic. The valence shell is ordered as shown in the answer.

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE

Otras preguntas