Answer:
[tex]f\left(x+\dfrac{5}{4}\right)[/tex] is function f(x) translated [tex]\frac{5}{4}[/tex] units left;
[tex]f(x)-\dfrac{5}{4}[/tex] is function f(x) translated [tex]\frac{5}{4}[/tex] units down.
Step-by-step explanation:
If the parent function has the equation [tex]y=f(x),[/tex] then the equations
- [tex]y=f(x+a)[/tex] represents translated a units to the left function f(x);
- [tex]y=f(x)-a[/tex] represents translated a units down function f(x).
So,
[tex]f\left(x+\dfrac{5}{4}\right)[/tex] is function f(x) translated [tex]\frac{5}{4}[/tex] units left;
[tex]f(x)-\dfrac{5}{4}[/tex] is function f(x) translated [tex]\frac{5}{4}[/tex] units down.
