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HELP ASAP 30 POINTS! GIVING BRAINLIEST TO THE CORRECT ANSWER

Which equation has the same solution as this equation?

x^2-16x+12=0

A) (x-8)^2 = 144

B) (x-4)^2 =4

C) (x-8)^2 = 52

D) (x-4)^2 = 16

Respuesta :

calculista

Answer:

Option C. [tex](x-8)^{2}=52[/tex]

Step-by-step explanation:

we have

[tex]x^{2}-16x+12=0[/tex]

Complete the square

[tex](x^{2}-16x+8^2)+12-8^2=0[/tex]

[tex](x^{2}-16x+64)+12-64=0[/tex]

[tex](x^{2}-16x+64)-52=0[/tex]

rewrite as perfect squares

[tex](x-8)^{2}-52=0[/tex]

Move the constant to the right side

[tex](x-8)^{2}=52[/tex]

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