Answer:
No effect will be observed since C is not included in the equilibrium expression.
Explanation:
Let's consider the following reaction.
CO₂(g) + C(graphite) ↔ 2 CO(g)
The equilibrium constant (Kc) is the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.
Kc only includes gases and aqueous species (not liquids or solids).
[tex]Kc=\frac{[CO]^{2}}{[CO_{2}]}[/tex]
As we can see, C is a solid and is not included in the equilibrium expression, so adding some C would have no effect on it.
The effect on the system will be:
B. No effect will be observed since C is not included in the equilibrium expression.
Chemical reaction:
CO₂(g) + C(graphite) ↔ 2 CO(g)
The equilibrium constant (Kc) is the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.
Kc only includes gases and aqueous species (not liquids or solids).
[tex]K_c=\frac{[CO]^2}{[CO_2]}[/tex]
Since, C is a solid and is not included in the equilibrium expression, so adding some C would have no effect on it.
Thus, option B is correct.
Find more information about Equilibrium constant here:
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