Answer:
Rise in temperature will be [tex]28.7^{\circ}C[/tex]
So option (c) will be the correct answer
Explanation:
We have given solar radiation on the panels [tex]=1000w/m^2[/tex]
25 % of the conversion efficiency = 25 % 1000 = 250
Area is given [tex]A=4m^2[/tex]
So radiated power [tex]P=250\times 4=1000watt[/tex]
Time is given t = 1 hour = 3600 sec
So energy [tex]E=power\times time=1000\times 3600=3.6\times 10^6J-sec[/tex]
Mass of water m = 30 kg
And [tex]c_w=4.186[/tex]
So rise in temperature [tex]\Delta T=\frac{Energy}{m\times c_w}=\frac{3.6\times 10^6}{30\times 4.186}=28.7^{\circ}C[/tex]
So option (c) will be the correct option
