Answer:
Yes, you would be safe without skidding off
Explanation:
In this situation the sum of forces on the car would be:
[tex]F_f = m*\frac{V^2}{R}[/tex]
[tex]F_f = 1900*\frac{13^2}{53}[/tex]
[tex]F_f = 6058.5N[/tex]
And the maximum friction force is:
[tex]F_fmax = \mu*N[/tex]
[tex]F_fmax = \mu*m*g[/tex]
[tex]F_fmax = 0.75*1900*10[/tex]
[tex]F_fmax = 14250N[/tex]
Since the required force is smaller than the maximum force, we can say it will not skid off
