Answer:
net outward force on a passenger's eardrum is 0.6115 N
Explanation:
Change in pressure is calculated as follows
[tex]\Delta P= \rho g h[/tex]
h= height of liquid column =480 m
ρ= density of liquid= 1.3 kg/m^3
putting values we get
[tex]\Delta P= 1.3\times9.8\times480 g h[/tex]
ΔP= 6115 Pa
Area of the eardrum is approximately
= 1 cm^2
Therefore, net force F = AΔP
= [tex]1\times10^{-4}\times6115[/tex]
= 0.6115 N
