Answer:
[tex]f=1480.52 Hz[/tex]
Explanation:
For the circuit of the radio knowing the voltage in a inductor is VL and the relation of element is:
[tex]V_L=I*Z_L*w[/tex]
Where [tex]I= 300mA[/tex], [tex]Z_L=4.3mH[/tex], [tex]V_L= 12V[/tex] and [tex]w=2\pi *f[/tex]
Knowing that the frequency influence in the performance of the inductor so:
[tex]V_L=I*Z_L*2\pi *f[/tex]
Solve to f'
[tex]f=\frac{V_L}{I*Z_L*2\pi } =\frac{12v}{300mA*43.mH*2\pi}[/tex]
[tex]f=1480.52 Hz[/tex]
