Answer:
a) 0.323m/s b) 54.278 m/s
Explanation:
The shell is moving upward with a speed of 17m/s
1.7s after it was launch
Using equation of motion on a straight line,
Vfinal = Vintial + acceleration due to gravity *time
Where V represent the speed(velocity)
Vinital = V(at 1.7s) - 9.81* 1.7
Vinital = 17 - 16.677
a) Vinital = 0.323m/s
b) using the same equation,
V(after 5.5s) = Vinital + 9.81*5.5s
Vafter5.5s = 0.323 + 53.955
V after 5.5s = 54.278m/s
