Answer:
The probability that the average score of the 49 golfers exceeded 62 is 0.3897
Step-by-step explanation:
The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5
[tex]\mu = 61[/tex]
[tex]\sigma = 3.5[/tex]
We are supposed to find he probability that the average score of the 49 golfers exceeded 62.
Formula : [tex]Z=\frac{x-\mu}{\sigma}[/tex]
[tex]Z=\frac{62-61}{3.5}[/tex]
[tex]Z=0.285[/tex]
Refer the z table for p value
p value = 0.6103
P(x>62)=1-P(x<62)=1-0.6103=0.3897
Hence the probability that the average score of the 49 golfers exceeded 62 is 0.3897
