Answer:
[tex]v=\sqrt{2gh}[/tex]
each tank hits the ground with same speed as above.
Explanation:
When fuel tanks are released there velocity u=0 m/s
all are released from the same height let it be h
let the velocity when they hit the ground be v
now using the equation
[tex]v^2-u^2=2gh[/tex]
where g= acceleration due to gravity
put u=o and rearranging we get
[tex]v=\sqrt{2gh}[/tex]
clearly, velocity is only dependent on the height h, which is same for all hence, we conclude that each tank hits the ground with same speed as above.
