Answer:
[tex]\sigma = 8.88 \times 10^6 \frac{1}{ohm-m}[/tex]
Explanation:
As we know that mobility of electrons is given as
[tex]\mu = \frac{v_d}{E}[/tex]
now we also know that
[tex]j = \sigma E[/tex]
here we know
[tex]j = ne v_d[/tex]
[tex]ne v_d = \sigma E[/tex]
so we have
[tex]\sigma = ne \frac{v_d}{E}[/tex]
[tex]\sigma = (3.7 \times 10^{28})(1.6 \times 10^{-19})(1.5 \times 10^{-3})[/tex]
[tex]\sigma = 8.88 \times 10^6 \frac{1}{ohm-m}[/tex]
