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In a biathlon , jackson cycled 9 miles in 3/4 of an hour in the first event. He than ran, on average, 7 miles per hour slower in the second event, which took him 1 1/2 hours. What is the distance that jackson ran in the second event ?

Respuesta :

Answer:

7.5 miles

Step-by-step explanation:

Given

  • In cycling,He covered 9 miles in [tex]\frac{3}{4}[/tex] hours,Therefore his avg cycling speed, u[tex]=\frac{Distance}{Time} =\frac{9}{\frac{3}{4} } =12\frac{miles}{hour}[/tex]
  • In second event, It took him [tex]1\frac{1}{2} =\frac{3}{2}[/tex]hours to complete,And his avg speed,v is  7[tex]\frac{miles}{hour}[/tex] slower than in previous event

⇒v= u-7

v= 12-7

v=5

Distance covered in 1st event[tex]=9miles[/tex]

Distance covered in 2nd event[tex]=Speed\times Time= 5\times \frac{3}{2} =7.5miles[/tex]

immalilladybug

Answer:

7 1/2

Step-by-step explanation:

because the dude under me was not thinking about the people who don't know what 7.5 mean it is 7 and .5 is half so 7 1/2

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