Answer:
tension in the string at the top position of the ball will be given as
T = 44.4 N
Explanation:
At the top position of the trajectory we have force equation given as
[tex]T + mg = \frac{mv^2}{R}[/tex]
here we have
[tex]T = \frac{mv^2}{R} - mg[/tex]
so we have
[tex]T = \frac{2(8^2)}{2} - (2 \times 9.8)[/tex]
[tex]T = 64 - 19.6[/tex]
[tex]T = 44.4 N[/tex]
So tension in the string at the top position of the ball will be given as
T = 44.4 N
