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In a test strength at a carnival, a hammer drives a metal weight up a rod to ring a bell at the top. If the bell is 24 ft above the starting position of the weight, what is the minimum initial vertical velocity needed to ring the bell?

In a test strength at a carnival a hammer drives a metal weight up a rod to ring a bell at the top If the bell is 24 ft above the starting position of the weigh class=

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MathPhys

Answer:

39 ft/s

Explanation:

Given:

Δy = 24 ft

v = 0 ft/s

a = -32 ft/s²

Find: v₀

v² = v₀² + 2aΔy

(0 ft/s)² = v₀² + 2 (-32 ft/s²) (24 ft)

v₀ ≈ 39 ft/s

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