Answer:
Shawn's kinetic energy is 61.45 J.
Explanation:
Given;
Mass of the system is, [tex]m=52.3\ kg[/tex]
Displacement of the bike is, [tex]d=1.6\ km=1.6\times 1000=1600\ m[/tex]
Time taken is, [tex]t=17.4\ min=17.4\times 60=1044\ s[/tex]
Let the constant velocity be [tex]v[/tex].
For constant velocity, magnitude of velocity is given as distance by time.
Therefore, [tex]v=\frac{d}{t}=\frac{1600}{1044}=1.533\ m/s[/tex]
Now, kinetic energy of a body is given as:
[tex]KE=\frac{1}{2}mv^2[/tex]
Here, [tex]m=52.3\ kg,\ v=1.533\ m/s[/tex]
[tex]\therefore KE=\frac{1}{2}\times 52.3\times (1.533)^2\\KE=0.5\times 52.3\times 2.35\\KE=61.45\ J[/tex]
Therefore, Shawn's kinetic energy is 61.45 J.
