Which is the graph of the linear inequality 2x – 3y < 12?

On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the right of the line is shaded.

On a coordinate plane, a dashed straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the right of the line is shaded.

On a coordinate plane, a dashed straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the left of the line is shaded.

On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the left of the line is shaded.

On a coordinate plane, a dashed straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the left of the line is shaded.

Step-by-step explanation:

1) This is our inequality:

[tex]2x-3y<12[/tex]

2) Since its first member is lesser than we'll trace a dashed line for the left side is not included.

3) The slope is the parameter that follow the x variable, in this case 2.

4) Plugging the points. To verify:

[tex]2x-3y<12[/tex]

[tex]2x-3y<12\\\\2(0)-3(-4)<12\\12<12 \:F\\2(3) -3(-2)<12\\6+6<12 \: F[/tex]

These points do not belong to the inequality, so the dashed line pass through these points.

Then it's

On a coordinate plane, a dashed straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the left of the line is shaded.