Answer:
[tex]M_{acid}=5.484x10^{-3}M[/tex]
Explanation:
Hello,
By using the following formula, which comes from the assurance of the equivalence point:
[tex]M_{acid}*V_{acid}=M_{base}*V_{base}\\M_{acid}=\frac{M_{base}*V_{base}}{V_{acid}}[/tex]
We just simply compute the acid's concentration (molarity), turning out into:
[tex]M_{acid}=\frac{0.2000M*22.62mL}{825mL} \\\\M_{acid}=5.484x10^{-3}M[/tex]
Best regards.
