The component of the force that moves the crate forward is equal to 7.1N(third option).
Why?
Since the force is applied at an angle (45°), the force has two components (horizontal and vertical). We can calculate the component that pushes the crate forward by the following way:
[tex]Force_{horizontal}=10N*Cos(45\°)=7.08N=7.1N[/tex]
Have a nice day!
