neilanymarquez1209 neilanymarquez1209

18-10-2019
Mathematics

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Determine the equations of the asymptotes: g(x)= [tex]\frac{2x^2+1}{x+3}[/tex]

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sqdancefan sqdancefan

18-10-2019

Answer:

x = -3
y = 2x -6

Step-by-step explanation:

The vertical asymptote is found where the denominator is zero, at x = -3.

The slant asymptote is the quotient of the division: 2x -6.

g(x) = (2x^2+1)/(x +3)

g(x) = 2x -6 +19/(x+3)

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