Answer:
B. 288. G
Explanation:
Moles of Al :
Given, Mass of Al = 20.4 g
Molar mass of Al = 26.9815 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{20.4\ g}{26.9815\ g/mol}[/tex]
[tex]Moles\= 0.7561\ mol[/tex]
The reaction between Al and I is shown below as:
2Al + 3I₂ ⇒ 2AlI₃
2 moles of aluminium react with 3 moles of iodine
1 mole of aluminium react with 3/2 moles of iodine
0.7561 moles of aluminium react with (3/2)*0.7561 moles of iodine
Moles of Iodine = 1.13415 moles
Molar mass of NaOH = 253.8089 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]1.13415\ Moles= \frac{Mass}{253.8089\ g/mol}[/tex]
Mass of Iodine = 288 g
