Answer:
resultant velocity of boat will be 11.2249 m/sec
Explanation:
We have given speed of boat [tex]v_b[/tex] = 10 m /sec
Velocity pf current flow [tex]v_c[/tex] = 4 m /sec
Angle at which boat is moving = 60°
We have to find the resultant velocity
We know that resultant velocity is given by [tex]v_r=\sqrt{v_b^2+v_c^2+2v_bv_rcos\Theta}=\sqrt{10^2+4^2+2\times 10\times 4cos60^{\circ}}=11.2249m/sec[/tex]
So resultant velocity of boat will be 11.2249 m/sec
