Answer:
[tex]V=\sqrt{\dfrac{2dqE}{m}}[/tex]
Explanation:
Given that
Mass = m
Electric filed = E
Initial velocity = 0 m/s
We know that
F= q E -----------1
F= m a --------2
a=Acceleration
F= Force
From equation 1 and 2
q E = m a
a= q E/m
We also know that
[tex]V^2=V_o^2+2aS[/tex]
So
Vo = 0
V²= 0² + 2 q E/m x d
[tex]V=\sqrt{\dfrac{2dqE}{m}}[/tex]
This is velocity of charge q after distance d .
