Answer:
package will strike at a distance of 244.7 m
Explanation:
Given data;
Velocity of plane 45 m/s
Acceleration due to gravity 9.8 m/s^2
horizontal component of plane velocity is ux = 45 m/s
vertical component is zero
in the same way
ay = - 9.8 m/s^2
ax = .0 m/s^2
motion in y direction = -145 m
from equation of motion time of flight is
[tex]s = ut + \frac{1}{2} at^2[/tex]
[tex]-145 = 0 + \frac{1}{2} (-9.8) t^2[/tex]
solving for t we get
t = 5.439 sec
Motion in x direction
[tex]s = ut + \frac{1}{2} at^2[/tex]
[tex]= (45 \times 5.43) + \frac{1}{2} (0) 5.43^2[/tex]
s = 244.79 m
Therefore package will strike at a distance of 244.7 m
