Two equations are given below:

a − 3b = 16
a = b − 2

What is the solution to the set of equations in the form (a, b)?

(−2, −6)

(−7, −9)

(−11, −9)

(−12, −10)

[tex] \left \{ {{a - 3b = 16} \atop {a = b - 2}} \right. \\ \\ \left \{ {{a = 16 + 3b} \atop { 16 + 3b = b - 2}} \right. \\ \\ \left \{ {{a = 16 + 3b} \atop {3b - b = - 2 - 16}} \right. \\ \\ \left \{ {{a =16 + 3b} \atop {2b = -18}} \right. \\ \\ \left \{ {{a=16 + 3b} \atop {b=-9}} \right. \\ \\ \left \{ {{a=16 + 3b = 16 + 3*(-9) = 16 - 27 = -11} \atop {b=-9}} \right. [/tex]

Answer a = -11, b = -9

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jordanjeanlouis05 jordanjeanlouis05 · Answer 2 · 2021-05-28T23:03:42+02:00

jordanjeanlouis05 jordanjeanlouis05

28-05-2021

Answer:

third one

Step-by-step explanation:

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Two equations are given below: a − 3b = 16 a = b − 2 What is the solution to the set of equations in the form (a, b)? (−2, −6) (−7, −9) (−11, −9) (−12, −10)

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Two equations are given below:

a − 3b = 16
a = b − 2

What is the solution to the set of equations in the form (a, b)?

(−2, −6)

(−7, −9)

(−11, −9)

(−12, −10)