Answer:
96.5 km/h
Explanation:
The average velocity of the train is given by:
[tex]v=\frac{d}{t}[/tex]
where
d is the displacement
t is the time taken
For this train, we have:
d = 55 km south (displacement is a vector, so we must also consider the direction)
[tex]t= 34 min \cdot \frac{1}{60 min/h}=0.57 h[/tex]
Substituting into the equation, we find the average velocity:
[tex]v=\frac{55 km}{0.57 h}=96.5 km/h[/tex]
