Answer:
3(10-3y)+4y=30
y=0
x=10
Step-by-step explanation:
You can replace 1 of the 2 variables in order to get a lineal equation.
First equation= 3x+4y=30
second equiation x+3y=10
Second= X=10-3Y--> Now you replace X In the first equation
3(10-3y)+4y=30
30-9y+4y=30
-5y=0
y=0
Now replace y with 0---> 3X+0=30--> X=10
So
y=0
x=10
Answer:
Hey just a heads up the answer is B
Step-by-step explanation:
I actually just did this exam on FLVS 4.03 Equivalent Systems
My answer from the test is found below.
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Question 10 (Worth 1 points)
(04.03 LC)
Given the following system of equations:
3x + 5y = 30
x + 3y = 10
Which action creates an equivalent system that will eliminate one variable when they are combined?
Multiply the second equation by −1 to get −x − 3y = −10.
Multiply the second equation by −3 to get −3x − 9y = −30.
Multiply the first equation by −1 to get −3x − 5y = −30.
Multiply the first equation by −3 to get −9x − 15y = −90.
Points earned on this question: 1
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Just wanted to get this out to those who need it, good luck on your test, and this is the answer, so your welcome!
