Explanation:
The given data is as follows.
V = 250.0 ml, T = 58^{o}C = 58 + 273 = 331 K
n = 2.48 moles, P = ? , R = 0.082 atm L /K mol
Therefore, calculate the pressure using ideal gas equation as follows.
PV = nRT
P = [tex]\frac{nRT}{V}[/tex]
= [tex]\frac{2.48 mol \times 0.082 atm L/K mol \times 331 K}{250.0 ml}[/tex]
= 0.269 atm
Thus, we can conclude that pressure of the given gas is 0.269 atm.
