contestada

A woman whose body mass is 50 kg rapidly stands from a sitting position with a peak vertical acceleration of 5 m/s2 directed upwards. Relative to her body weight, what percent increase is the peak magnitude of the ground reaction force?

Respuesta :

Answer:51.02

Explanation:

Given

mass of woman(m)=50 kg

acceleration (a)[tex]=5 m/s^2[/tex]

Force acting on woman is

mg

Normal reaction(N)

Thus

N-mg=ma

N=m(g+a)

[tex]N=50\times (9.8+5)=740[/tex]

Original Normal reaction=mg

[tex]N_0=50\times 9.8=490 N[/tex]

% increase[tex] =\frac{N-N_0}{N_0}[/tex]

[tex]=\frac{740-490}{490}=0.5102[/tex]

51.02 %

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