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As we exercise, our bodies metabolize glucose, converting it to CO2 and H2O, to supply the energy necessary for physical activity. The simplified reaction is:
C6H12O6(aq)+6O2(g)→6CO2(g)+6H2O(l)+678kcal(2840kJ)
An individual weighing 150 pounds jogging at 5 mph for 30 minutes would burn 328 kcal. How many moles of glucose would need to be metabolized to generate this required energy?

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luchoprat luchoprat · Answer 1 · 2019-09-20T13:30:35+02:00

Answer:

0.484 mole

Explanation:

1 mole of glucose reacts with 6 moles of O2, producing :

6 moles of CO2

6 moles of H2O

678 kcal

Using rule of three you have:

1 mole of glucose -> 678 kcal

x mole of glucose -> 328 kcal

x = 328/678 * 1 =0.484 mole

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adefioyelaoye adefioyelaoye · Answer 2 · 2022-04-01T11:56:11+02:00

0.484 mole of glucose would be needed to be metabolized to generate this required energy.

This is used to express amounts of reactants and products in a chemical reaction.

1 mole of glucose reacts with 6 moles of O2 to produce :

6 moles of CO2

6 moles of H2O

678 kcal

From this we can infer that:

1 mole of glucose = 678 kcal

x mole of glucose = 328 kcal

x = 328/678 * 1 =0.484 mole.

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