Answer:
Flux will be [tex]2.711\times 10^6Nm^2/C[/tex]
Explanation:
We have given point charge [tex]q=48\mu C=48\times 10^{-6}C[/tex]
As the point charge is located at very small distance from the center of large square
So the large square behaves as like infinite plane
We know that due to infinite plane electric flux is given by
[tex]\Phi =\frac{q}{2\epsilon _0}[/tex]
So flux [tex]\Phi =\frac{q}{2\epsilon _0}=\frac{48\times 10^{-6}}{2\times 8.85\times 10^{-12}}=2.711\times 10^6Nm^2/C[/tex]
