Ben
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If you know that [tex]m\angle EHF=90^{\circ}[/tex] and that [tex]m\angle GHF=90^{\circ}[/tex], what property/properties can you use to prove that [tex]m\angle EHF=m\angle GHF[/tex]? Explain your answer.

If you know that texmangle EHF90circtex and that texmangle GHF90circtex what propertyproperties can you use to prove that texmangle EHFmangle GHFtex Explain you class=

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znk

Answer:

I would use Euclid's first axiom:

Step-by-step explanation:

Things that are equal to the same thing are equal to each other.

[tex]\begin{array}{rcl}m\angle EHF & = & 90^{\circ} \text{ (Given)}\\m\angle GHF & = & 90^{\circ} \text{ (Given)}\\\therefore m\angle EHF & = & m\angle GHF \text{ (Euclid Axiom 1)} \\\textbf{QEF} & & \\\end{array}[/tex]

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