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In a double-slit experiment, the third-order maximum for light of wavelength 520 nm is located 10 mm from the central bright spot on a screen 1.6 m from the slits. Light of wavelength 660 nm is then projected through the same slits. How far from the central bright spot will the second-order maximum of this light be located? Express your answer in meters using two significant figures.

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Answer:

Explanation:

The distance of n the bright fringe is given by the formula

x = nλD/d

here x = 10 x 10⁻³ m

λ = 520 x 10⁻⁹

n = 3

D = 1.6 m

d = 2.496 x 10⁻⁴ m

for second case ,

n =2, λ = 660 x 10⁻⁹ , D = 1.6 d = 2.496 x 10⁻⁴

x = 2 x 660 x 10⁻⁹ x 1.6 /2.496 x 10⁻⁴m   = 8.46 mm.

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