Calculate the wavelength of the Ka X-ray emitted from a Zinc target (Z = 30) when an electron moves from higher shell to the Kshell (n = 1).

Respuesta :

Answer:

[tex]\lambda = 1.45*10^{-10} m[/tex]

Explanation:

wavelength of K_a X ray can be computed by using following relation

[tex]\frac{1}{\lambda} = R(Z-1)^2 [\frac{1}{n_1^2 - \frac{1}{n^2_2}}][/tex]

for K_a ray, [tex]n_1 = 1, n_2 = 2[/tex]

therefore

[tex]\frac{1}{\lambda} = R(30-1)^2 [\frac{1}{1} - \frac{1}{4}][/tex]

[tex]\frac{1}{\lambda} = \frac{R*841*3}{4}[/tex]

[tex]\lambda = \frac{4}{R*841*3}[/tex]

Where R is Rydberg constant = 1.097 *10^7 m^{-1}

[tex]\lambda = \frac{4}{1.097 *10^7*841*3}[/tex]

[tex]\lambda = 1.45*10^{-10} m[/tex]

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