Answer:
Capacitance, C = 26.1 picofarad
Explanation:
It is given that,
Side of square, x = 4.3546 cm = 0.043546 m
Distance between electrodes, d = 0.6408 mm = 0.0006408 m
Voltage, V = 73.68 V
Capacitance of parallel plates is given by :
[tex]C=\dfrac{\epsilon_oA}{d}[/tex]
[tex]C=\dfrac{8.85\times 10^{-12}\times (0.043546)^2}{0.0006408}[/tex]
[tex]C=2.61\times 10^{-11}\ F[/tex]
or
C = 26.1 picofarad
So, the capacitance of the capacitor is 26.1 picofarad. Hence, this is the required solution.
