Answer:
The height of Sears Tower is 1448.5 feet.
Explanation:
We apply the free fall formula to the ball:
[tex]y=v_{o} *t+\frac{1}{2} *g*t^{2}[/tex]
y: The vertical distance the ball moves at time t
[tex]v_{o}[/tex]i: Initial speed
g=Gravity acceleration=[tex]9.8*(\frac{\frac{1ft}{0.305m} }{s^{2} } )[/tex]
Known information
We know that the vertical distance (y) that the ball moves in 9,5s is equal to height of Sears Tower (h).
Too we know that the ball is released from rest, then,[tex]v_{0}[/tex]=0
Height of Sears Tower calculation:
We replace in the equation 1 the data following;
[tex]y=h[/tex]
[tex]v_{o} =0[/tex]
[tex]g=32,1\frac{ft}{s^{2} }[/tex]
[tex]t= 9,5s[/tex]
[tex]h=0*9.5+\frac{1}{2} *32.1*9.5^{2}[/tex]
[tex]h=1448.5 ft[/tex]
Answer: The height of Sears Tower is 1448.5 ft
