A 79-turn, 16.035-cm-diameter coil is at rest in a horizontal plane. A uniform magnetic field 43 degrees away from vertical increases from 0.997 T to 6.683 T in 56.691 s. Determine the emf induced in the coil.

Respuesta :

Answer:

The induced emf is 0.0888 V.

Explanation:

Given that,

Number of turns = 79

Diameter = 16.035 cm

Angle = 43

Change in magnetic field [tex]\Delta B=(6.683-0.997)= 5.686\ T[/tex]

Time = 56.691 s

We need to calculate the induced emf

Using formula of induced emf

[tex]\epsilon=\dfrac{NA\Delta B\cos\theta}{\Delta T}[/tex]

Where, N = number of turns

A = area

B = magnetic field

Put the value into the formula

[tex]\epsilon=\dfrac{79\times\pi\times(8.0175\times10^{-2})^2\times5.686\times\cos43}{56.691}[/tex]

[tex]\epsilon =0.0888\ V[/tex]

Hence, The induced emf is 0.0888 V.

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