Answer:
0.68 sec
Explanation:
let the velocity be "v" when the angle is 30° .
Consider the motion along the horizontal direction
[tex]v_{ox}[/tex] = initial velocity of ball along horizontal direction = 25 Cos50
= 16.07 m/s
[tex]v_{fx}[/tex] = final velocity of ball along horizontal direction = v Cos30
we know that along the horizontal direction
[tex]v_{fx}[/tex] = [tex]v_{ox}[/tex]
v Cos30 = 16.07
v = 18.56 m/s
Consider the motion along the vertical direction
[tex]v_{oy}[/tex] = initial velocity of ball along vertical direction = 25 Sin50
= 19.2 m/s
[tex]v_{fy}[/tex] = final velocity of ball along vertical direction = v Sin30 = 25 Sin30 = 12.5 m/s
[tex]a_{y}[/tex] = acceleration = - 9.8 m/s²
[tex]t[/tex] = time taken
using the equation
[tex]v_{fy} = v_{oy} + a_{y} t [/tex]
12.5 = 19.2 + (- 9.8) t
t = 0.68 sec
